Chapter 04 of 11 · Chief Mate

Ship Handling & Manoeuvring

Turning, stopping and squeezing through shallow water are three different physics problems wearing the same hull — get the pivot point, the speed-squared effects and the pressure fields right and manoeuvring stops feeling like guesswork.

Worked examples3, fully stepped
Read time≈ 15 min
PrerequisiteNone

1. Turning circle geometry and the moving pivot point

Put the wheel hard over from a steady course and the ship traces a roughly circular path with three named landmarks on it. Advance is how far she has travelled in her original direction by the time the heading has swung 90°. Transfer is the sideways displacement over that same swing. Tactical diameter is the transfer once she has turned a full 180° — the distance between the original track and the reciprocal one. A fourth figure, final diameter, is the steady circle she settles onto once the initial transients have died away, and it is usually a little smaller than the tactical diameter. All four come from sea trials and sit on the pilot card, and all four change with loading, trim and speed, so a ballast-passage figure is not a laden-arrival figure.

Pivot point ≈ L/3 abaft the bow, going ahead shifts toward the stern going astern

The reason the turning circle has the shape it does is the pivot point — the point on the centreline that appears, for a moment, to not be moving sideways at all. Forward of it the hull is being pushed bodily into the turn; aft of it, the flow past the stern and the rudder's side force are doing the steering. Going ahead that balance sits roughly a third of the ship's length back from the bow. Put her astern and the flow over the hull reverses, the rudder's authority drops away, and the pivot point slides aft — often close to the stern, sometimes beyond it. That single fact explains why a ship that answers her wheel crisply going ahead can feel unresponsive and unpredictable going astern: the bow, now well forward of the pivot, describes a much wider arc than it did on the way in.

The key idea

The pivot point is not a fixed point on the hull — it is a balance point that moves continuously with headway, sternway, rate of turn and any thrust from bow or stern thrusters. Treat every turning-circle figure as a snapshot at one speed, one loading and one moment, not a constant.

2. Stopping distances and headreach

An engine order of full astern does not stop a ship the way brakes stop a car. There is a delay while the engine actually reverses — longer on a large slow-speed diesel than a manual candidate might expect — and once astern thrust does arrive it is fighting the ship's momentum, not simply cancelling it. The distance covered from the order being given to the ship coming to rest is her headreach, and it is one of the few manoeuvring figures with a genuinely simple physical basis: kinetic energy goes as the square of speed, and the astern propeller is doing roughly constant work against it, so headreach scales with speed squared rather than speed itself.

Headreach ∝ V² (roughly, constant retarding thrust) halve the speed, cut headreach to about a quarter

That squared relationship is the whole reason "slow down early" beats "stop late" — a modest reduction in approach speed buys a disproportionate reduction in the distance needed to stop. It also means the reverse is true: a small speed increase over what the pilot card was worked from eats far more stopping distance than it looks like it should. A crash stop is also rarely a straight line. A right-handed propeller driven astern generates transverse thrust that walks the stern to port, so the ship curves away from her original track as she slows — useful to know if the reason for the crash stop was something dead ahead, because "stopped" and "stopped on the original track" are not the same promise.

The key idea

Headreach figures from trials are a starting point, not a guarantee — add margin for engine response lag, for the sheer as the stern kicks one way, and for the fact that trial conditions (calm water, clean hull, full power available) are usually better than the conditions you are actually stopping in.

3. Squat and the shallow-water effect

Run a ship into shallow water and the flow that has to pass under and around the hull is forced through a smaller gap. By continuity that flow speeds up, and by Bernoulli's principle the pressure under the hull drops as it does — so the ship sinks bodily and usually trims as well, typically by the head on a full-form vessel and sometimes by the stern on a fine one. That combined sinkage-plus-trim is squat, and because it grows with the square of speed it is cheap to control and expensive to ignore: a small reduction in speed buys a large reduction in squat, for very little time lost on passage.

S(max) = Cb·V²/100 — open water S(max) = Cb·V²/50 — confined channel V in knots, S in metres; confined water roughly doubles it for the same speed

"Confined" here means a channel narrow or shallow enough relative to the ship's beam and draught that the water displaced by the hull cannot escape sideways as easily as it can in open water — a river, a dredged channel, a fairway between banks. The block coefficient matters because a full-form hull (high Cb) shoves more water aside for a given length than a fine one, so it squats more at the same speed. None of this is visible from the bridge in the way a list or a trim is visible — it has to be worked out, which is exactly why it gets forgotten under pressure.

The key idea

Depth of water comes from chart plus tide; UKC comes from that depth minus draught; squat is then subtracted from what's left. Checking the chart depth against the draught and stopping there — without adding the tide first and taking squat off after — is the single most common way of talking yourself into a passage that isn't actually there.

4. Interaction — banks, channels and other ships

A moving hull sets up a pressure field around itself, and that field reacts against anything solid nearby — a bank, the channel bed, or another ship's hull. Run close to a bank on one side and the flow accelerating between hull and bank creates suction that draws the stern toward the bank, while the bow, meeting slower water and a building pressure wave ahead of it, is pushed away. The net effect is a ship that wants to swing her bow off the bank and drag her stern onto it — exactly the wrong direction to correct for instinctively if you are not expecting it.

The same mechanism operates between two ships. Meeting or overtaking close aboard in a channel, each hull's bow-wave and each hull's suction zone act on the other: bows are pushed apart, midship sections are pulled together. It is worse the closer the passing distance, worse the higher the speed of either vessel, and worse still when overtaking, because the ships remain close aboard for far longer than they do in a passing situation on opposite courses — plenty of time for a sheer to develop and for a slow correction to arrive too late.

The key idea

Interaction is a squeeze effect, not a collision-course effect — it can act on ships that are never going to touch and never set an alarm off, so the only real defences are distance and speed: open the passing distance where the channel allows it, and reduce speed (which reduces the pressure differential) where it does not.

  • Bank effect — bow pushed off, stern drawn on, strongest in a narrow dredged channel.
  • Bow cushion — the pressure wave ahead of an approaching or overtaking hull that pushes another ship's bow away.
  • Interaction suction — the low-pressure zone amidships that pulls hulls together once bows have passed.
  • Squat-interaction combination — shallow water and close passing together are worse than either alone, since both effects grow as the available water around the hull shrinks.

5. Anchoring practice and tug operations

An anchor holds mainly through the friction and resistance of cable lying along the seabed, not through the anchor's flukes alone — which is why scope (the ratio of cable paid out to depth of water) matters more than the size of the anchor once it is on the bottom. More scope lays the cable flatter, pulling on the anchor at a lower angle and letting it dig in rather than break out. A common starting point in settled weather is cable of roughly four to six times the depth of water, increased well beyond that as wind or current build, since holding power comes from added scope and a longer catenary far more than from extra weight sitting on the bottom.

Scope ≈ 4–6 × depth (fair weather), more in strong wind or current a starting point to work from, not a fixed rule

Tugs introduce their own hazard, distinct from anything the ship herself is doing: girting, where a tug made fast by a conventional towline is pulled round beam-on to her own tow and capsized by the very force she is meant to be applying. Escort tugs are built and operated to avoid this, working in a direct mode (essentially towing, force along the line) or an indirect mode (the tug's hull generates hydrodynamic lift at an angle to the line, steering the towed ship with far less risk of girting at speed). Either way, the figure printed on a tug's specification — bollard pull — is the static pull at zero speed, straight astern; the steering force she can actually deliver to the ship depends heavily on the angle of the line and the mode she is working in, and is often a good deal less than the headline number suggests.

6. Berthing, unberthing and handling in heavy weather

Berthing is turning-circle theory and interaction theory applied at low speed and short range. A spring line run out and taken to a winch, combined with ahead or astern power against the rudder, lets the ship pivot on the wire and bring the bow or stern in without needing to fight the whole hull sideways — far gentler on the berth and on the ship than trying to crab in on thrusters alone. Wind and current on the beam matter more here than at sea, because windage acts on a hull that has very little speed to give the rudder any bite, so a berthing plan has to account for which way the wind is setting the ship onto or off the berth before the first line goes ashore, not after.

In open water and heavy weather the priorities shift to keeping the hull intact and comfortable rather than making a plan. Reducing speed in head or bow seas cuts slamming and green water on deck; altering course to broaden the angle of the sea does the same by changing the relative encounter period. Two specific dangers are worth knowing by name: synchronous rolling, where the wave encounter period matches the ship's natural roll period and the roll builds cycle on cycle, and parametric rolling, where large, rapid changes in waterplane area as a ship pitches in a head or following sea — most often a fine-formed hull with large bow and stern flare — pump energy into a roll that was never being directly excited by the waves at all. Both are avoided the same way: change the encounter period by altering course or speed rather than riding it out and hoping it settles.

The key idea

Heavy-weather shiphandling is about not agreeing with the sea's timing — matching course and speed to break any resonance between the wave pattern and the ship's own natural periods, rather than holding a fixed course and speed and accepting whatever that produces.

7. Worked examples

Three fully stepped problems below: a squat-and-UKC speed limit, a turning-circle wheel-over check against available sea room, and a headreach scaling check for a crash stop. Work each one before reading the answer.

Worked example 1

Maximum safe speed on a shallow patch, using squat and required UKC

Your ship, drawing 11.00 m, is inbound through a narrow channel and must cross a charted shoal. Charted depth at the shoal is 12.30 m (chart datum) and the tide at the time of crossing will add 1.20 m. The passage plan requires a minimum under-keel clearance (UKC) of 1.00 m at all times, and the channel is narrow enough that the confined-channel squat formula applies. The block coefficient (Cb) is 0.75. What is the fastest speed you can safely maintain over the shoal?

Given

Draught, d = 11.00 m Charted depth at shoal (chart datum) = 12.30 m Predicted tide at time of crossing = +1.20 m Required minimum UKC (passage plan) = 1.00 m Block coefficient, Cb = 0.75 Channel classed as confined (width restricts flow around the hull)

Required

What is the fastest speed you can safely maintain over the shoal?

  1. First convert the chart figures into the actual depth of water under the keel at the moment of crossing — chart datum is not what is there on the day.

    H=charted depth + tide =12.30 + 1.20 =13.50 m
  2. Static UKC — before the ship starts moving — is simply that depth of water minus the draught.

    UKC(static)=H − d =13.50 − 11.00 =2.50 m
  3. The margin you're allowed to spend on squat is whatever is left once the passage-plan minimum is set aside; nothing closer than that is acceptable, however busy the channel.

    S(max)=UKC(static) − UKC(min) =2.50 − 1.00 =1.50 m
  4. The channel is confined.

    S(max)=Cb × V² / 50 1.50=0.75 × V² / 50 V²=1.50 × 50 / 0.75 = 100 V=10.0 kn

    So use the confined-water form of the squat formula rather than the open-water one — picking the wrong one halves the predicted squat for the same speed and quietly halves your real margin.

AnswerMaximum speed over the shoal ≈ 10.0 knots through the water — and since this is the ceiling, not a target, the prudent speed to actually run is a knot or two below it.

The trap: using the open-water squat formula (÷100) in what is really a confined channel — it understates squat by half and hands the candidate a false margin of safety.

Worked example 2

Wheel-over point for a 90° bend, and whether there's sea room to make it

Approaching a 90° bend in a buoyed channel, you need to check whether there is still room to execute the turn as planned. From the pilot card, the ship's tactical diameter at the current manoeuvring speed is 640 m. The ECDIS shows 280 m of track remaining to the corner. Should you be putting the wheel over now?

Given

Tactical diameter at manoeuvring speed, TD = 640 m Course alteration required at the bend, θ = 90° Distance remaining to the corner (from ECDIS) = 280 m

  1. Tactical diameter is measured across the completed circle.

    R=TD / 2 =640 / 2 =320 m

    So halve it to get the turning radius the ship will actually trace — using the diameter directly here would double every distance that follows.

  2. The wheel has to go over before the corner, not at it.

    D(wheel-over)=R × tan(θ/2) =320 × tan(45°) =320 × 1.00 =320 m

    For a course change of θ on a constant-radius turn, the wheel-over distance back from the intersection point is R × tan(θ/2) — here θ is a clean 90°, so tan(45°) is exactly 1.

  3. Compare that with what's actually left on the chart.

    Shortfall=D(wheel-over) − distance remaining =320 − 280 =40 m
  4. Forty metres of shortfall means the wheel should already be going over.

    Ordering it now will still swing the ship onto the new leg a little late, carrying her further into the bend than the plotted track allows before she steadies — call it now, and be ready to check the swing with a touch of counter-rudder once she's coming round, rather than waiting for the corner itself.

AnswerWheel over now (already ≈40 m late) — expect to steady onto the new track slightly wide of the plotted corner unless the swing is checked.

The trap: using tactical diameter as if it were the turning radius — forgetting to halve it doubles the calculated wheel-over distance and can make a turn that's already late look comfortably early.

Worked example 3

Scaling headreach with speed to check a crash stop

Sea trial data for your ship shows a crash-stop headreach of 8 ship lengths from a full sea speed of 16 knots (LOA 250 m). You are currently making 12 knots with a charted danger 1200 m ahead. If you had to order a crash stop right now, would the ship stop clear?

Given

Trial headreach at 16 kn = 8 ship lengths Ship's length overall, LOA = 250 m Current speed = 12 kn Distance to danger ahead = 1200 m

  1. Convert the trial figure from ship lengths into metres.

    Headreach(16 kn)=8 × LOA =8 × 250 =2000 m

    Since the danger ahead is charted in metres.

  2. Headreach isn't proportional to speed.

    Headreach(12 kn)=Headreach(16 kn) × (12/16)² =2000 × 0.5625 =1125 m

    It's proportional to speed squared, because the astern thrust does roughly constant work against a kinetic energy that itself goes as V². Scale the trial figure down to the current speed on that basis.

  3. Now compare the scaled headreach with what's actually ahead.

    Margin=distance to danger − headreach(12 kn) =1200 − 1125 =75 m
  4. Seventy-five metres sounds like clearance.

    But it isn't much once engine response lag, the ship's tendency to sheer off track under astern thrust, and the trial figure's own margin of error are allowed for. Treat this as 'might just stop in time', not as a demonstrated safe margin — the sensible response was to have reduced speed well before the gap closed to this.

Answer≈1125 m of headreach needed at 12 kn against 1200 m available — a bare 75 m margin, too thin to rely on; speed should have come off earlier.

The trap: assuming headreach scales linearly with speed — cutting speed by a quarter (16 to 12 kn) does not cut stopping distance by a quarter, it cuts it by nearly 44%, which flatters small speed reductions and, read the other way, badly understates how much extra room a small speed increase eats up.

Reference sheet
60-second recall
  1. Headreach scales with speed squared, not speed — a small speed cut buys a big stopping-distance saving.
  2. Wheel-over point = turning radius × tan(half the course change) — work it out before the bend, not at it.
  3. Squat is subtracted after the tide is added — check UKC with both, not depth alone.
  4. Overtaking in a channel is worse than meeting — interaction has far longer to act at similar speeds.
  5. Bollard pull is not steering force — towline angle and towing mode decide what a tug can actually deliver.