Chapter 02 of 11 · Master

Stability, Strength & Loading

A loading condition is never approved on one number. It has to clear intact stability, a damage case, the hull girder's strength limits and whatever the cargo itself is doing, all at once, at every stage from berth to arrival.

Worked examples3, fully stepped
Read time≈ 15 min
PrerequisiteNone

1. Approving the condition — every criterion, one signature

Every loading condition that goes in front of the master for approval is being checked against several completely independent standards at the same time, and it only takes one of them to fail for the whole condition to be refused. The intact stability criteria from the IS Code have to be met. Any damage case the ship is required to survive has to be met. The hull girder's still-water bending moment and shear force have to sit inside the approved limit curves. The tank tops and decks have to carry what is stowed on them without local overload. And the trim and draught have to fit whatever the port, canal or berth allows. None of these substitutes for another — a condition can clear every intact stability check and still be refused because the tank top under one hold is carrying more than it is rated for.

The loading computer does the arithmetic, and on a modern ship it will flag a failure clearly enough. What it will not do is decide which of several possible stowage plans is sensible, or notice that a condition which passes on paper depends on a ballast tank that nobody has actually sounded being exactly where the plan assumes it is. The master's signature is the point at which someone takes responsibility for having read the output, not merely for having run it — worth keeping in mind before treating a green light on a screen as the end of the exercise.

The key idea

Approval is a set of independent pass/fail tests, not one number. A condition is only as good as its weakest criterion, and that criterion is not always the one you expected to be tight.

2. Intact stability — the IS Code minima, and what each one guards against

The IS Code's intact criteria look like an arbitrary list of numbers until you separate what each one is actually protecting against. GM₀ has to be at least 0.15 m — that is the floor on initial stiffness, the tendency to come back upright from a small angle before anything about the ship's shape further out matters. The righting lever at 30° of heel, GZ₃₀, has to reach at least 0.20 m, and the angle at which GZ is greatest, θmax, has to be at least 25°. Those two together are less about the first few degrees and more about how much righting force is still being generated well into a roll, which is exactly where a beam sea or a gust puts a ship under way.

The area criteria go further still: the area under the GZ curve from 0° to 30° must reach 0.055 m·rad, from 0° to 40° (or the angle of downflooding, if that comes sooner) must reach 0.090 m·rad, and from 30° to 40° must reach 0.030 m·rad. Area under a curve of righting lever against angle is energy — the work the ship can absorb from wind and sea before she is pushed past the point of no return. A ship can satisfy GM₀ comfortably and still fail an area criterion if her GZ curve falls away quickly past 20° or so, which is exactly the shape a high, slab-sided deck cargo or a full grain hold tends to produce.

GM₀ ≥ 0.15 m   GZ₃₀ ≥ 0.20 m   θmax ≥ 25°   the three intact minima, checked together, not separately

3. Damage stability and the arrival case

The damage case a ship has to survive depends on her type and her damage stability notation, and it is worked from an assumed extent of flooding rather than from any single accident the ship happens to be expected to have. What the calculation gives back is a residual condition — GM, range of stability and freeboard with one or more compartments open to the sea — that still has to clear its own, generally lower, minima. A condition that comfortably clears the intact criteria can still fail the damage case if too much of the ship's reserve buoyancy and stability margin has already been spent getting her down to a deep, upright, intact trim in the first place.

The point examiners keep coming back to is the arrival condition. Consumables — fuel, fresh water, stores — are drawn from tanks that sit low and are burned off progressively over a voyage, so KG on arrival is not the same as KG on departure; it is very often higher, because the weight lost has come off the bottom of the ship. A stowage plan approved against a comfortable departure GM can arrive with a GM that is thin, or with a damage case that no longer clears its minima, purely because of how the consumables were drawn down. Approving a condition on the departure figures alone, without running the arrival case, is treating half the voyage as though it did not exist.

4. Longitudinal strength and local loading limits

The hull girder is a beam, and the still-water bending moment and shear force it carries at any point along its length depend on how weight is distributed against the buoyancy supporting it. Concentrate cargo over one part of the ship and leave another part light, and the beam bends more than the same total tonnage spread evenly would produce. The ship's approved loading manual gives permissible SWBM and shear force curves along the length, separately for hogging and sagging, and every condition — harbour or at sea — has to sit inside them. Because the curves are tightest at particular stations, usually somewhere near amidships, two stowage plans with the same total deadweight can produce very different bending moments.

Local loading is a separate question from the overall bending moment. A tank top or deck is rated in tonnes per square metre, not tonnes — the total weight in a hold says nothing about whether the steel underneath one stack of cargo or one pile of bulk can take it. And because a ship is loaded and ballasted in a sequence, not delivered fully stowed in one moment, the bending moment and shear force have to be checked at each intermediate stage of that sequence as well as on completion. It is common, not exceptional, for the tightest moment of the whole operation to occur partway through loading, before the ballast intended to counteract it has actually been discharged.

SWBM, SF ≤ permissible curve   hogging and sagging, harbour and sea, at every stage
  • Total deadweight — tells you almost nothing about bending moment on its own.
  • Distribution along the length — what actually drives SWBM and shear force.
  • Tonnes per square metre — the separate check on the tank top or deck itself.

5. The heavy lift — rise of G at the derrick head

A weight resting on deck acts at its own height above the keel, wherever that happens to be. The moment a crane or derrick takes the strain and lifts it clear, that stops being true — the load is now being carried into the ship's structure through the point of suspension, so for the purposes of GG and GM it behaves as though it had been moved bodily up to the derrick head, however high above the deck that happens to sit. The shift in G this produces, w·d/Δ, where d is the vertical distance from the weight's original position to the derrick head, can be a large fraction of the GM the ship had to begin with, particularly on a ship carrying a light GM to start with or lifting a genuinely heavy piece of plant.

The examinable point is timing. The rise in G happens at the instant the load comes off the deck, not gradually as the boom slews it outboard and not only once it is set down somewhere else — the ship has to be stable enough to take the lift the moment the wire takes the strain, wherever the derrick subsequently swings it. If the derrick head also stands off the centreline once the load is plumbed outboard — over the quay, over a barge alongside — the same logic applies transversely, and the ship takes up a list from the shift in G across the beam as well as up it. Both effects have to be worked before the lift is taken, not discovered afterwards from how the ship is actually sitting.

Rise of G = w·d/Δ   d = weight's position to derrick head — apply it the instant the wire takes the strain

6. Grain stability — heeling moments and residual area

Grain is a granular cargo with no fixed surface of its own — trimmed as full as practicable, it still settles and can shift its own free surface at an angle of repose when the ship rolls, and any void left above a trimmed surface, however small, gives it room to do so. The Grain Code's answer is to require a heeling moment to be calculated for every compartment that is not completely full and trimmed, tabulated against the compartment's shape and fill, and to check the resulting condition against its own criteria: an initial GM of at least 0.30 m, an angle of heel that does not exceed 12° or the angle of deck-edge immersion, whichever comes first, and a residual area between the heel angle and 40° (or the downflooding angle) of at least 0.075 m·rad.

None of those three checks stands in for another. The GM requirement sits above the general intact minimum precisely because a grain ship carries a standing risk of a shifting cargo that an ordinary dry cargo does not present. The heel-angle limit caps how far she is allowed to go over if the worst tabulated shift actually happens. The residual area is the reserve of righting energy left over after that heel has already been taken up — the margin still available to survive weather on top of the shift itself. A partly filled compartment is not a minor exception to work around; it is the specific condition the whole of this calculation exists to control, and every one of the three checks has to be run against it.

Grain: GM₀ ≥ 0.30 m   heel ≤ 12° (or deck-edge immersion)   residual area ≥ 0.075 m·rad
The key idea

A partly filled hold is not a rounding error in the stability calculation — it is the actual case the Grain Code's three checks are written to catch.

7. Worked examples

The three conditions below are worked the way a loading computer's audit trail, or an oral exam, expects to see them — a given block, each reasoning step shown before its arithmetic, and a decision stated in plain terms at the end.

Worked example 1

Rise of G during a heavy lift, and the list it causes

A general cargo ship of 8000 t displacement is discharging a heavy lift with her own gear. The lift, 100 t, is resting on deck at a height of 8.00 m above the keel while it is being slung. The derrick head is 20.00 m above the keel and, when plumbed over the quay, stands 5.20 m outboard of the centreline. At the load waterline KM is 7.80 m and KG, with the lift still resting on deck, is 7.00 m. Find the ship's GM the instant the lift comes clear of the deck, and the list she takes as the derrick swings the load out over the quay.

Given

Δ = 8000 t KM = 7.80 m KG (lift still on deck) = 7.00 m w (lift) = 100 t, resting at 8.00 m above the keel Derrick head height = 20.00 m above the keel Derrick head outreach from centreline = 5.20 m

Required

Find the ship's GM the instant the lift comes clear of the deck, and the list she takes as the derrick swings the load out over the quay

  1. The instant the wire takes the weight, the lift no longer acts at its resting height.

    d=20.00 − 8.00 = 12.00 m (deck to derrick head) Rise of G=w·d/Δ =100 × 12.00 / 8000 =0.15 m

    It acts as though concentrated at the derrick head, because that is the point through which its full weight is now carried into the ship's structure.

  2. That rise applies the moment the load leaves the deck.

    KG₁=7.00 + 0.15 = 7.15 m GM₁=KM − KG₁ =7.80 − 7.15 =0.65 m

    Whether or not it has swung anywhere yet, so the new KG and GM follow immediately.

  3. Swinging the derrick out over the quay carries the load.

    GG₁ (transverse)=w × outreach / Δ =100 × 5.20 / 8000 =0.065 m

    And therefore G, off the centreline too, by the same w·d/Δ logic applied transversely.

  4. The resulting list follows the usual small-angle relationship between an off-centre G and the righting lever.

    tan θ=GG₁ / GM₁ =0.065 / 0.65 =0.100 θ=arctan(0.100) ≈ 5.7°

AnswerGM at the moment of lift ≈ 0.65 m (well above the IS Code's 0.15 m floor); the ship takes a list of about 5.7° as the derrick plumbs the quay.

The trap: forgetting that a weight still hanging from the ship's own gear is still part of Δ and still has to be worked at the derrick head — it has not left the ship just because it has left the deck.

Worked example 2

Grain-loaded GM, free surface, and the heeling-moment check

A bulk carrier completes loading a parcel of grain. Displacement is 15,000 t, KM is 8.20 m and KG, taken solid with no free-surface allowance, is 7.65 m. Two holds are left partly filled after trimming; the loading computer returns a free-surface correction of 0.15 m for them and a total transverse grain heeling moment of 900 t·m. Check the condition against the Grain Code's GM and heel-angle limits.

Given

Δ = 15,000 t KM = 8.20 m KG (solid) = 7.65 m Free-surface correction (FSC) = 0.15 m Total transverse grain heeling moment = 900 t·m Grain Code minima: GM₀ ≥ 0.30 m; heel ≤ 12°

Required

Check the condition against the Grain Code's GM and heel-angle limits

  1. Start from the solid GM.

    GM (solid)=KM − KG =8.20 − 7.65 =0.55 m GM (fluid)=0.55 − 0.15 =0.40 m

    Then take off the free surface of the slack grain before anything else — FSC is a deduction from GM in its own right, separate from the heeling moment that comes next.

  2. Check the fluid GM against the Grain Code's own floor.

    0.40 m vs 0.30 m required →GM check passes, 0.10 m in hand

    Which sits above the general intact minimum because a grain ship carries a standing shifting risk that an ordinary dry cargo does not.

  3. The heeling moment then gives the angle the ship actually takes up if the grain shifts, using the fluid GM already corrected above.

    tan θ=heeling moment / (Δ × GM) =900 / (15,000 × 0.40) =900 / 6000 =0.150 θ=arctan(0.150) ≈ 8.5°
  4. 8.5° clears the 12° (or deck-edge immersion.

    If that comes first) limit, but the residual dynamical stability area out to 40° or the downflooding angle still has to be read off the ship's approved grain-loading data — GM and the heeling moment alone cannot confirm it.

AnswerGM (fluid) = 0.40 m, above the 0.30 m floor; heel on a full grain shift ≈ 8.5°, within the 12° limit. The residual-area check still has to be confirmed from the approved grain booklet.

The trap: quoting the 0.40 m fluid GM as though it were the finished grain check — the free-surface correction, the heeling-moment/heel-angle test and the residual-area requirement are three separate hurdles, and a partly filled hold feeds all three.

Worked example 3

Which loading stage actually governs — strength and tank-top loading

A vessel's loading computer outputs the still-water bending moment (SWBM, hogging) at three points in a loading sequence, together with the permissible SWBM from the ship's approved limit curve at this draught. Hold No. 3 has a tank-top area of 240 m² and is to take 960 t of cargo, stowed evenly. The stability booklet gives a permissible tank-top loading of 5.00 t/m². Find which stage comes closest to the strength limit, and check the tank-top loading.

Given

Permissible SWBM (hogging), this draught = 210,000 t·m SWBM, intermediate stage (Hold 3 loaded, ballast not yet discharged) = 199,500 t·m SWBM, departure (loading complete) = 185,000 t·m SWBM, arrival (after consumables burned) = 178,500 t·m Hold 3 tank-top area = 240 m² Cargo into Hold 3 = 960 t Permissible tank-top loading = 5.00 t/m²

Required

Find which stage comes closest to the strength limit, and check the tank-top loading

  1. Work out how close each stage comes to the permissible curve.

    SWBM against the permissible limit
    StageSWBM (t·m)% of permissible
    Intermediate (loading)199,50095.0%
    Departure185,00088.1%
    Arrival178,50085.0%
    Permissible210,000100%

    Not just the finished condition — the order in which holds fill and ballast is discharged can put the hull girder under more load partway through than at the end.

  2. The intermediate stage.

    Not departure or arrival, is the one that actually governs this loading sequence — it leaves only about 5% of the permissible moment in hand.

  3. Separately, check the tank top itself.

    Tank-top loading=cargo / area =960 / 240 =4.00 t/m² 4.00 t/m² vs 5.00 t/m² permissible →passes, at 80% of the limit

    The total tonnes in the hold say nothing about whether the plating underneath can take it; that depends on how the load is spread over the area.

AnswerThe intermediate loading stage governs, at 95% of the permissible SWBM — departure and arrival both carry more margin. Tank-top loading is 4.00 t/m², within the 5.00 t/m² limit.

The trap: approving the condition off the departure figure alone (185,000 t·m looks comfortable) and never checking the loading sequence itself, where the moment actually peaks closer to the limit.

Reference sheet
60-second recall
  1. GM₀ ≥ 0.15 m is the intact floor — the IS Code area checks are what actually carry a ship through a seaway.
  2. A suspended weight still counts in Δ — it just acts higher up, at the derrick head.
  3. Outreach lists the ship too — a heavy lift shifts G sideways as well as up.
  4. Free-surface correction and the grain heeling moment are two separate deductions from GM.
  5. The loading sequence can be tighter than the finished stow — check the intermediate stages, not just the end.